In each situation, recognize the worth of the constant c that renders the probcapacity statement correct.

You are watching: In each case determine the value of the constant c

$P(c le |Z|)=0.016$

Here is my attempt:

$P(|Z| ge c)=0.016$

$P(Z ge c~or~Z le -c) = 0.016 $

$<1-phi (c)> - phi (-c) = 0.016$

By symmeattempt, $1-phi (c)$ and also $phi (-c)$ are equal.

$2 phi (-c) = 0.016 suggests phi (-c) = 0.008$.

However before, this does not bring about the correct solution. What exactly did I fix for? And just how was I actually intend to solve this question?

You started correctly: We want a merged probability of $0.016$ in the 2 tails $Zge c$ and also $Zle -c$. By symmetry, we desire a probcapacity of $frac0.0162=0.008$ in the "right tail."

Equivalently, we want $Pr(Zle c)=1-0.008=0.992$. Look for $0.9992$ in the **body** of your standard normal table.

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