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Q: How many 7s in 56?

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There is one 7s orbital with two sub-orbitals: 7s(+1/2) and 7s(-1/2) . A picture of this 7s orbital is in 'Related links'

5.28751 7s equals 37.

Two electrons (each with opposite spins) in the '7s orbital'

answer:4

6

-8 x 7/12 = -56/12 or -4 and 2/3

80.

18

14

5

10

2 electrons

Expressed algebraically, this would equal 7s - 5.

18/7

4

100

Exactly 30 of them

13

14

11 r3

There are: 777/7 = 111

7, remainder 2

210 ÷ 7 = 30

There are normally two.

The answer is 7s + 49.